% trnglDef.m
%          16 JUne 2004
%                  from   TrikoorinEnglish.m
% 
% Here the compositions by Tex (Swedish painter) are coded. 
% Each composition consists of three colored triangles. 
% Each triangle is determined by the x- and  y-coordinates for the 
% leftmost corner and by the angle between a vertical
% and the side down to lowest corner. Each coordinate is given by eight
% bits. For x and y the resolution will be 0.5 mm.
% Angles are determined by seven bits. The resolution will thus be one
% degree.
% Each triangle is colored red, green or blue. The intensity for each color
% is given by two bits. A red triangle thus has the color vector 
% [1 1 0 0 0 0], a green triangle has the color vctor [0 0 1 1 0 0].
% Each composition thus has 3(8+8+7+6) = 87 bits.

% First all coordinates are given as binary numbers.
A1t = [0 0 1 0 0 0 1 0  0 0 1 0 0 1 1 0  1 0 1 1 0 1 0  0 0 0 0 1 1
       0 1 0 1 0 0 1 0  0 0 1 1 1 1 1 0  1 0 1 1 0 1 0  0 0 0 0 1 1
       0 0 0 0 1 0 1 0  0 1 1 0 0 1 1 0  1 0 1 1 0 1 0  0 0 0 0 1 1]';
A1 = A1t(:);

% to recover original decimal coordinates/data
A1d = [pow2(6:-1:-1)*A1t(1:8,:) 
       pow2(6:-1:-1)*A1t((1:8)+8,:)
       pow2(6:-1:0)*A1t((1:7)+16,:)
       [2 1]*A1t((1:2)+23,:)
       [2 1]*A1t((1:2)+25,:)
       [2 1]*A1t((1:2)+27,:)]' ;
 
% to recreate the binary representation  A1b == A1t
A1b = [dec2bin(2*A1d(:,1),8) dec2bin(2*A1d(:,2),8) dec2bin(A1d(:,3),7) ...
       dec2bin(A1d(:,4),2) dec2bin(A1d(:,5),2) dec2bin(A1d(:,6),2)]' - '0' ;
   
A2tri1=[0 0 1 1 1 1 1 0 0 0 0 1 1 1 0 0 1 0 1 1 0 1 0 0 0 0 0 1 1];
A2tri2=[0 1 0 0 1 1 0 0 1 0 0 0 0 0 0 1 1 0 1 1 0 1 0 0 0 0 0 1 1];
A2tri3=[0 0 0 0 1 0 0 1 0 1 0 0 1 0 1 0 1 0 1 1 0 1 0 0 0 0 0 1 1];
A2=[A2tri1 A2tri2 A2tri3];
A2=A2';
A3tri1=[0 0 0 1 0 0 0 0 1 0 0 1 0 1 0 0 1 0 1 1 0 1 0 0 0 0 0 1 1];
A3tri2=[0 0 1 0 1 1 0 0 0 0 0 1 1 0 0 1 1 0 1 1 0 1 0 0 0 0 0 1 1];
A3tri3=[0 0 1 0 0 1 0 1 0 1 0 1 1 0 1 0 1 0 1 1 0 1 0 0 0 0 0 1 1];
A3=[A3tri1 A3tri2 A3tri3];
A3=A3';
A4tri1=[0 0 0 1 0 1 0 1 1 0 0 1 0 1 0 0 1 0 1 1 0 1 0 0 0 0 0 1 1];
A4tri2=[0 1 0 1 0 0 0 0 0 1 1 1 0 1 0 0 1 0 1 1 0 1 0 0 0 0 0 1 1];
A4tri3=[0 0 0 1 1 1 0 1 0 0 0 1 1 1 0 1 1 0 1 1 0 1 0 0 0 0 0 1 1];
A4=[A4tri1 A4tri2 A4tri3];
A4=A4';
A5tri1=[0 1 0 1 0 1 1 0 0 1 1 1 1 0 0 0 1 0 1 1 0 1 0 0 0 0 0 1 1];
A5tri2=[0 0 0 1 0 0 1 0 1 0 0 0 0 0 0 0 1 0 1 1 0 1 0 0 0 0 0 1 1];
A5tri3=[0 0 1 0 0 0 1 0 0 0 1 0 0 0 1 0 1 0 1 1 0 1 0 0 0 0 0 1 1];
A5=[A5tri1 A5tri2 A5tri3];
A5=A5';

% All the coordinates of the A-compositions are stored in a matrix.
TA=[A1 A2 A3 A4 A5]; % is 87 x 5

B1t = [0 0 0 1 1 1 0 0 1 0 0 1 1 0 1 1 0 1 0 0 1 0 1 1 1 0 0 0 0
       0 1 0 0 1 0 0 1 0 1 1 0 1 1 1 0 1 1 0 0 1 0 1 0 0 0 0 1 1
       0 0 0 1 1 1 0 1 0 1 0 0 1 0 0 1 0 1 0 1 0 1 1 0 0 1 1 0 0]' ;
B1 = B1t(:) ;

% to recover original decimal coordinates/data
B1d = [pow2(6:-1:-1)*B1t(1:8,:) 
       pow2(6:-1:-1)*B1t((1:8)+8,:)
       pow2(6:-1:0)*B1t((1:7)+16,:)
       [2 1]*B1t((1:2)+23,:)
       [2 1]*B1t((1:2)+25,:)
       [2 1]*B1t((1:2)+27,:)]' ;
   
 %    x     y     o  r  g  b
 %   14    77.5  37  3  0  0
 %   36.5  55.  101  0  0  3
 %   14.5  36.5  43  0  3  0
 
% to recreate the binary representation  B1b == B1t
B1b = [dec2bin(2*B1d(:,1),8) dec2bin(2*B1d(:,2),8) dec2bin(B1d(:,3),7) ...
       dec2bin(B1d(:,4),2) dec2bin(B1d(:,5),2) dec2bin(B1d(:,6),2)]' - '0' ;

B2tri1=[0 0 1 1 1 1 1 0 0 0 1 0 1 1 0 0 0 1 0 1 1 0 1 0 0 0 0 1 1];
B2tri2=[0 0 0 1 0 1 1 1 0 1 0 0 0 1 0 0 1 1 0 0 1 0 1 0 0 1 1 0 0];
B2tri3=[0 0 1 0 1 0 1 0 1 0 0 1 1 1 1 0 0 1 0 0 1 1 0 1 1 0 0 0 0];
B2=[B2tri1 B2tri2 B2tri3];
B2=B2';
B3tri1=[0 1 1 0 1 0 1 0 1 0 0 0 0 0 0 1 1 1 0 1 0 1 0 0 0 1 1 0 0];
B3tri2=[0 0 1 0 1 0 0 0 0 0 1 1 1 0 1 0 0 1 0 1 0 0 1 1 1 0 0 0 0];
B3tri3=[0 0 0 0 1 1 0 0 0 1 1 1 0 0 1 1 1 0 0 0 0 1 1 0 0 0 0 1 1];
B3=[B3tri1 B3tri2 B3tri3];
B3=B3';
B4tri1=[0 0 0 1 0 0 0 1 1 0 0 1 0 1 0 1 1 0 0 0 1 1 0 1 1 0 0 0 0];
B4tri2=[0 1 0 1 0 0 0 0 1 0 0 0 0 1 0 1 0 1 0 0 0 1 1 0 0 1 1 0 0];
B4tri3=[0 0 0 1 1 1 1 1 0 1 1 0 0 0 0 0 0 0 1 0 0 1 1 0 0 0 0 1 1];
B4=[B4tri1 B4tri2 B4tri3];
B4=B4';
B5tri1=[0 0 1 0 0 0 0 0 1 0 1 0 1 0 0 0 0 0 0 0 0 0 0 1 1 0 0 0 0];
B5tri2=[0 0 1 0 1 0 1 0 0 0 1 0 1 1 0 0 0 1 1 1 1 0 0 0 0 0 0 1 1];
B5tri3=[0 0 1 0 1 0 1 0 0 1 1 1 0 1 1 1 0 1 1 1 0 1 0 0 0 1 1 0 0];
B5=[B5tri1 B5tri2 B5tri3];
B5=B5';

% All the coordinates of the B-compositions are stored in a matrix.

TB=[B1 B2 B3 B4 B5];

D1tri1=[0 1 0 0 0 0 1 0 0 0 0 1 1 0 1 0 1 0 1 1 0 1 0 0 0 1 1 0 0];
D1tri2=[0 0 0 1 1 0 1 1 0 1 1 0 1 0 1 1 0 0 0 0 0 0 0 1 1 0 0 0 0];
D1tri3=[0 0 1 0 1 0 1 1 1 0 0 0 0 1 1 0 0 1 1 1 1 0 0 0 0 0 0 1 1];
D1=[D1tri1 D1tri2 D1tri3];
D1=D1';

D2tri1=[0 0 1 0 1 1 1 1 0 0 1 1 0 0 0 1 0 0 0 1 0 1 0 0 0 0 0 1 1];
D2tri2=[0 1 0 1 0 0 0 1 0 1 0 0 0 0 1 0 1 0 1 1 0 1 0 1 1 0 0 0 0];
D2tri3=[0 0 0 0 1 1 0 0 0 1 1 0 0 1 0 0 1 1 0 0 1 1 1 0 0 1 1 0 0];
D2=[D2tri1 D2tri2 D2tri3];
D2=D2';

D3tri1=[0 0 1 1 1 0 0 0 0 1 0 0 0 1 1 0 1 0 1 1 0 1 0 0 0 1 1 0 0];
D3tri2=[0 0 1 0 1 1 0 1 0 0 1 1 1 1 1 0 0 0 1 1 1 1 0 0 0 0 0 1 1];
D3tri3=[0 0 0 1 1 0 1 1 1 0 1 0 0 1 0 1 0 0 1 1 1 1 0 1 1 0 0 0 0];
D3=[D3tri1 D3tri2 D3tri3];
D3=D3';

D4tri1=[0 0 1 1 1 0 0 0 0 1 1 0 0 0 0 1 1 0 1 0 1 0 1 0 0 0 0 1 1];
D4tri2=[0 0 1 0 1 1 1 1 0 0 1 1 1 0 1 0 0 1 0 1 1 0 1 0 0 1 1 0 0];
D4tri3=[0 0 0 1 1 1 1 1 0 1 1 1 0 1 0 0 1 0 0 0 1 0 0 1 1 0 0 0 0];
D4=[D4tri1 D4tri2 D4tri3];
D4=D4';

D5tri1=[0 0 1 0 0 0 1 1 1 0 1 0 0 0 0 0 0 0 1 1 1 1 0 0 0 1 1 0 0];
D5tri2=[0 0 1 1 1 1 0 0 0 1 0 0 0 1 1 0 0 0 1 1 1 1 0 0 0 0 0 1 1];
D5tri3=[0 0 1 0 1 1 1 0 1 0 0 0 0 1 1 0 0 0 0 0 0 0 0 1 1 0 0 0 0];
D5=[D5tri1 D5tri2 D5tri3];
D5=D5';

% All the coordinates of the D-compositions are stored in a matrix.

TD=[D1 D2 D3 D4 D5];

% Since Hopfield uses -1 instead of 0 we make the exchange:
TA = 2*TA - 1;  % is 87 by 5
TB = 2*TB - 1;
TD = 2*TD - 1;


T = [TA TB TD];  % is 87 by 15

% Now we add noisy versions of D.

rand('seed',sum(100*clock))

 TBRUS1 = T ;
 prt = [8 16 23 37 45 52 66 74 81];
 TBRUS1(prt, :) = sign(rands(size(prt,2), 15)) ;

TBRUS2=[T(1:6,:)
sign(rands(2,15))
T(9:14,:)
sign(rands(2,15))
T(17:21,:)
sign(rands(2,15))
T(24:29,:)
T(30:35,:)
sign(rands(2,15))
T(38:43,:)
sign(rands(2,15))
T(46:50,:)
sign(rands(2,15))
T(53:58,:)
T(59:64,:)
sign(rands(2,15))
T(67:72,:)
sign(rands(2,15))
T(75:79,:)
sign(rands(2,15))
T(82:87,:)];

TBRUS3=[T(1:5,:)
sign(rands(3,15))
T(9:13,:)
sign(rands(3,15))
T(17:20,:)
sign(rands(3,15))
T(24:29,:)
T(30:34,:)
sign(rands(3,15))
T(38:42,:)
sign(rands(3,15))
T(46:49,:)
sign(rands(3,15))
T(53:58,:)
T(59:63,:)
sign(rands(3,15))
T(67:71,:)
sign(rands(3,15))
T(75:78,:)
sign(rands(3,15))
T(82:87,:)];

TBRUS4=[T(1:4,:)
sign(rands(4,15))
T(9:12,:)
sign(rands(4,15))
T(17:19,:)
sign(rands(4,15))
T(24:29,:)
T(30:33,:)
sign(rands(4,15))
T(38:41,:)
sign(rands(4,15))
T(46:48,:)
sign(rands(4,15))
T(53:58,:)
T(59:62,:)
sign(rands(4,15))
T(67:70,:)
sign(rands(4,15))
T(75:77,:)
sign(rands(4,15))
T(82:87,:)];

TBRUS5=[T(1:3,:)
sign(rands(5,15))
T(9:11,:)
sign(rands(5,15))
T(17:18,:)
sign(rands(5,15))
T(24:29,:)
T(30:32,:)
sign(rands(5,15))
T(38:40,:)
sign(rands(5,15))
T(46:47,:)
sign(rands(5,15))
T(53:58,:)
T(59:61,:)
sign(rands(5,15))
T(67:69,:)
sign(rands(5,15))
T(75:76,:)
sign(rands(5,15))
T(82:87,:)];

TBRUS6=[T(1:2,:)
sign(rands(6,15))
T(9:10,:)
sign(rands(6,15))
T(17,:)
sign(rands(6,15))
sign(rands(6,15))
T(30:31,:)
sign(rands(6,15))
T(38:39,:)
sign(rands(6,15))
T(46,:)
sign(rands(6,15))
sign(rands(6,15))
T(59:60,:)
sign(rands(6,15))
T(67:68,:)
sign(rands(6,15))
T(75,:)
sign(rands(6,15))
sign(rands(6,15))];