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Second Order extension

As a result, a second order estimate for the binomial distribution can be derived as -


 \begin{displaymath}
\begin{split}
\textrm{MesgLen} &= -\log_e \theta^{m+\frac{1}...
...c{m+\frac{1}{2}}{m+n+1} = \frac{m+\frac{1}{2}}{N+1}
\end{split}\end{displaymath} (54)



Edmund Lam
2000-12-04